Maximal Ideal/Ring homomorphism question

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SUMMARY

The discussion centers on the properties of ring homomorphisms, specifically regarding prime and maximal ideals. It establishes that if T: R -> S is a ring homomorphism and J is a maximal ideal of S, then T-1(J) is not necessarily maximal in R. The example provided involves the integers R and the integers mod 7 S, where T is defined as the mapping from Z to Z mod 7. The conclusion emphasizes that an embedding must be injective, and the inclusion homomorphism from the integers to the reals is suggested as a valid example.

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Homework Statement


So I have a question that says:

Let T:R -> S be a ring homomorphism, show that if J is a prime ideal of S, then

T-1(J) := { r in R s.t. T(r) is in J)

is a prime ideal of R. (I've done this bit)

It then says:
Give an example where J is maximal but T-1(J) is not maximal, hint: consider a suitable embedding T of a ring into a field


Homework Equations



First thing that doesn't really help is that I'm not so clear of what an 'embedding of a ring into a field' actually means in the first place. This is a phrase that crops up but has never been properly defined in my course.


The Attempt at a Solution



Ok so if I let R = integers and S = integers mod 7, then I think T taking a in Z to its equivalence class mod 7 defines an embedding of the integers into the field Z mod 7. However the only ideals in Z mod 7 are the whole field, and {0}. The pre-image of the whole field is clearly the whole of Z, whereas the pre-image of {0} is the set 7Z which is also a maximal ideal since 7 is prime. Bit confused, have tried a few other examples but can't get anything to work/understand the hint.
 
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Zoe-b said:
Ok so if I let R = integers and S = integers mod 7, then I think T taking a in Z to its equivalence class mod 7 defines an embedding of the integers into the field Z mod 7.

An embedding is necessarily injective. Your mapping is not injective so it is not an embedding. For this problem consider the inclusion homomorphism [itex]\mathbb{Z} \rightarrow \mathbb{R}[/itex] and recall that the only maximal ideal in a field is [itex]\{0\}[/itex].
 

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