Maximizing Cone Volume Inside a Sphere

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SUMMARY

The discussion focuses on determining the dimensions of a right circular cone that maximizes volume when inscribed in a sphere with a radius of 15 cm. The mathematical approach involves using the equation V=(1/3)πr²(√(225-r²) + 15) to derive the volume in terms of the radius r. The critical equation 9r^4 - 2670r^2 + 195750 = 0 is solved to find the optimal radius, resulting in r ≈ 11.5 cm and height h ≈ 24.63 cm, yielding a maximum volume of approximately 3411.05 cm³.

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Homework Statement


Find the dimensions of the right circular cone of maximum volume that can be inscribed in a sphere of radius 15cm.

Homework Equations


The Attempt at a Solution



let r be radius of circular base of cone
let y be height of small right triangle
let h be height of cone
r^2 + y^2=225
y=sqrt(225-r^2)

h=15+y

V=(1/3)pir^2(sqrt(225-r^2) + 15)

Now to find V'...I get to 9r^4-2670r^2+195750 = 0
0=3(3r^4-890r^2+65250)

Need to solve for r.

Took about 2323 lines.

Final dimensions; r=11.5 roughly

h=24.63

maax volume is 3411.05 ?
 
Last edited:
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Can somebody confirm this? Thank you :)
 

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