Maximizing Electrostatic Force between Two Point Charges

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Vishakha
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Homework Statement


Two point charges q and λq located at the points, x=a & x=μa respectively. If the sum of the two charges is constant,what is the value of λ for which the magnitude of the electrostatic force is maximum?

Homework Equations


The Attempt at a Solution


For force to be maximum dF/dq =0 and d^F/dq^2 <0. When I tried to calculate dF/dq =0 I got λ=0.
 
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BvU said:
Well, how did you do that? Can you post your steps in detail ?

By the way: why calculate ##dF\over dq## ?

I already wrote that in The attempt at a solution section.

F= λq2/4πε0 (μa-a)2
⇒ dF/dq = 2λq/4πε0(μa-a)2 =0
⇒ 2λq = 0
q≠0 ⇒λ=0
 
If you want to find the maximum of a function of x you take the derivative wrt x.
Here, do you want to consider the force as a function of q ?

Note also that you forgot to make use of the given that
Vishakha said:
the sum of the two charges is constant
 
BvU said:
If you want to find the maximum of a function of x you take the derivative wrt x.
Here, do you want to consider the force as a function of q ?

Note also that you forgot to make use of the given that
If I used q+λq = C ⇒ λq=C-q
Then 2λq=0 ⇒ 2(C-q) = 0 ⇒q=C

Let F is function of distance

F = λq2/4πε0a2(μ-1)2
⇒ -2λq2/4πε0a3(μ-1)2 = 0
⇒ -2λq2 = 0
⇒ λq= 0 or λq=C
 
BvU said:
Are you saying ##\lambda = 0 \Rightarrow F = 0 ## too ? That is easily proven wrong !

You are right. F shouldn't be zero but I don't find any mistake in my calculation.
 
Vishakha said:
I don't find any mistake in my calculation
I did and I tried to point it out. You want to express F in terms of ##\lambda## and differentiate wrt ##\lambda##. Make a start ...
 
BvU said:
I did and I tried to point it out. You want to express F in terms of ##\lambda## and differentiate wrt ##\lambda##. Make a start ...

You mean I have to differentiate F wrt λ and distance between charges and q is constant.
 
BvU said:
Yes and No. In that order:

λ+qλ = C
⇒dq = -(q+1)dλ/λ ... (1)

dF/da = [(μa-a)2 { 2λq dq + q2 dλ} - 2q2λa (μ-1)2 ]/ 4πε0 (μa-a)2 = 0

After putting value of eq (1) I got final eq
-q(q+1) dλ = 2λa
 
Last edited:
Can you explain why you are now differentiating wrt a ? I thought we agreed to seek a value for ##\lambda## that gives the maximum ##F## ?

And: do you think we can leave out the constants ##\displaystyle {1\over 4\pi\varepsilon_0 (\mu a - a)^2 } ## ?
 
BvU said:
And: do you think we can leave out the constants ##\displaystyle {1\over 4\pi\varepsilon_0 (\mu a - a)^2 } ## ?

I got λ=1 if we leave the constants.

But I don't understand why are we differentiating wrt λ?
 
Vishakha said:
I got λ=1 if we leave the constants.

But I don't understand why are we differentiating wrt λ?
Because the problem asks, "what is the value of λ for which the magnitude of the electrostatic force is maximum?"
 
Vishakha said:
I got λ=1 if we leave the constants.

But I don't understand why are we differentiating wrt λ?
Can you explain how you found ##\lambda = 1 ## ?
And can you justify leaving out the constants ? Why is that allowed ?