Maximizing Fuel Efficiency: Calculating Gas Mileage for a 20% Efficient Car

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SUMMARY

The discussion focuses on calculating the gas mileage of a car with a 20% engine efficiency and an average retarding force of 1000 N. The energy content of gasoline is specified as 40 megajoules per liter. The initial calculation attempted dividing 40 MJ by 1000 N, resulting in 40,000 meters, which was then converted to 40 km per liter. After applying the 20% efficiency factor, the final result is determined to be 8 km per liter, confirming the method's validity.

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  • Basic arithmetic skills for performing calculations involving percentages.
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Homework Statement



A car's engine is 20% efficient. When cruising, the car encounters an average retarding force of 1000 N. If the energy content of gasoline is 40 megajoules per liter, how many kilometers per liter does the car get?


The Attempt at a Solution



What I tried to do it divide 40 MJ per liter by 1000 N = 40000 meters. I then converted to km per liter which gave me 40km per liter. I think multiplied by 20% and got 8 km per liter. I am not quite sure if this was the right method.
 
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Looks OK to me.
 
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