Crush1986
- 205
- 10
Homework Statement
Gasoline has an energy content of 9.38 × 10^5 J/oz. If a car,
with a mass of 1500 kg, is accelerated to a speed of 29.1
m/s, how much gas is consumed by the engine, assuming
40% efficiency?
Homework Equations
w=fd
w= ΔKE
The Attempt at a Solution
So I started by multiplying the energy content of gasoline by .4 so I believe I could just treat it was being 100 percent efficient after that.
I then calculated the KE the car had at the end of it's acceleration. 1/2*(1500kg)*(29.1 m/s)^2 = 635107.5 J. I then divided this by the amount of energy a car uses per oz of gasoline which was .4 * 9.38*10^5 J/oz to get the oz's. Which was 1.69.
Is this all correct?
Thank you to anyone for their time.