Saitama
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haruspex said:No, I mean the point at which there is no gradient. When no more heat can be pumped into B, the temperatures of A and C will be equal, right? That gives you your third equation.
From these you can extract a cubic in one unknown. Now, solving a cubic is a lot easier if you happen to know one root. Here's where the problem setter has been kind to you - you do already have one solution to it. (Hint)
I got a cubic in one unknown,
2T_{A1}^3-1000T_{A1}^2+32\times 10^6=0
Honestly, I can not figure out that one root and had to use a calculator. The calculator gave me 2 positive roots, 256.16 and 400. The second root indicates that no heat is extracted from A, I don't see how this could have been obvious to me. :(
Corresponding to these two values of ##T_{A1}##, I get ##T_{B1}## equal to 200 and 487.67. Is 487.67 the correct answer?
I haven't been able to understand why the total change in entropy is constant? How did you even bring this relation? Have I missed out anything in my notes? If so, please give me a link which explains this.haruspex said:...the max temp achievable will correspond to no change in entropy..