Maximizing MOSFET Switching Speed with High Voltage Pulse Techniques

  • Thread starter Thread starter ctech4285
  • Start date Start date
  • Tags Tags
    Mosfet Switch
Click For Summary
MOSFET switching speed is influenced by the rise and fall times of the source and drain, which depend on the gate voltage's rise and fall time. Applying a high voltage briefly can charge or discharge the gate quickly, but there are limits to avoid damaging the MOSFET. The gate's distributed resistance and capacitance create a time delay in turning on the gate, and the channel formation requires time for carriers to flow from the source or drain. While MOSFETs can switch on rapidly, the turn-on time cannot be zero. Overclocking CMOS circuits can lead to failure due to excessive energy dissipation.
ctech4285
Messages
31
Reaction score
0
ok looking at datasheets for mostfet there is source/drain rise and fall time. does this only depend on the voltage rise fall time of the gate?
so if you apply a voltage to the gate it will take a wile until the voltage of the actual gate reaches that of the applied voltage because of resistance and capacitance of the gate. so you could apply a very high voltage for a short a time to charge discharge the gate as fast as you possible want. maybe a few 100V timed to exactly the time needed for the gate to reach let's say 10V, maybe nano/pico seconds. now of course there will be a point at which you burn enough energy to blow up the mosfet
 
Engineering news on Phys.org
Since the gate has distributed resistance and capacitance, it acts like an RC transmission line. This means there is a time delay to turn on the gate, no matter how much voltage you apply. Also, it takes a finite time for the channel to form once the threshold voltage is exceeded, since the carriers to form the channel need to flow out from the source or drain. Mosfets can turn on very quickly (in ps), but the turn on time can never be zero.
 
now of course there will be a point at which you burn enough energy to blow up the mosfet
That's the reason CMOS circiuts blow up when you overclock them.
 
so the entire process is just a electrons flowing from the gate. and so you can model this as restive flow from he gate...thank for clarifying this!
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
39
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 6 ·
Replies
6
Views
10K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
1
Views
3K
Replies
19
Views
2K