- #1
hopkid
- 9
- 0
Homework Statement
a) For the mechanism shown in figure 1 determine for the angle (45°):
i) the velocity (VBO) of the piston relative to the fixed point (O).
ii) the angular velocity of AB about point A.
iii) the acceleration of point B relative to A.
*Note: Link AB is horizontal when angle = 45°.
b) Determine the value of the angle (measured from vertical) when:
i) the velocity of point b = 0.
ii) the angular velocity of link AB a maximum.
c) what is the maximum angular velocity of link AB?
Homework Equations
v=lw (a)r = v^2/l
The Attempt at a Solution
l of AO = 50mm = 0.05m
l of AB = 200mm = 0.2m
w of AO = 300 x 2pi/60 = 31.42 rads^-1
ai) V of AO = l of AO x w of AO.
V of A0 = 0.05 x 31.42
V of AO = 1.57ms^-1
*Use this value to draw a velocity diagram (attached).
To confirm using trig,
Sin(45°) = V of BO/1.57
V of BO = 1.57 x Sin(45°)
V of BO = 1.11ms^-1
aii) v=lw therefore w=v/l
w of AB = v of AB/l of AB
w of AB = 1.11/0.2
w of AB = 5.55 rads^-1
aiii) (a of BA)r = v of BA^2/l of BA
(a of BA)r = 1.11^2/0.2
(a of BA)r = 6.16ms^-2
*Tangential velocity is calculated in the acceleration diagram (attached).
Radial acceleration of AO calculated below to use in the diagram.
(a of AO)r = v of AO^2/l of AO
(a of AO)r = 1.57^2/0.05
(a of AO)r = 49.3ms^-2
So, as per the diagram, (a of BA)t = 34.5ms^-2.
This is the part where I am starting to struggle, I have had conformation back from my tutor that the first 3 parts to the question look good but I am struggling with parts b & c.
If someone could help push me in the right direction then it would be very much appreciated. I am after guidance, not answers, I want to learn.
