Maximum and Minimum Values (Trig)

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Homework Help Overview

The discussion revolves around finding the four critical points of the function f(x,y) = 5ycos(9x) that are closest to the origin (0,0). The problem involves concepts from calculus, specifically related to critical points and trigonometric functions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the notation for coordinates and the correct ordering of x and y. There are attempts to derive the critical points using derivatives, with some confusion about the spacing of solutions and how to express them correctly. Questions about the validity of the calculated points and their proximity to the origin are also raised.

Discussion Status

The discussion is ongoing, with participants providing feedback on each other's attempts and questioning the accuracy of the derived points. Some guidance is offered regarding the format of the solutions, but there is no clear consensus on the correct critical points as multiple interpretations are being explored.

Contextual Notes

There is mention of an automatic checking system that may have specific requirements for input formats, which adds a layer of complexity to the problem-solving process. Participants express uncertainty about how to present their answers to meet these requirements.

Chas3down
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Homework Statement


Find the 4 critical points f(x,y) = 5ycos(9x) closest to (0,0)

Homework Equations

The Attempt at a Solution



fx = -45ysin(9x)
fy = 5cos(9x)
fxx = -45*9ycos(9x)
fyy = 0
fxy = -45sin(9x)

y=0
x=pi/18

(0,pi/18) (0,pi/18 + pi/2) (0,pi/18 - pi/2) (0,pi/18 + 3pi/2) Was not correct.

(All 4 points need to be correct for me to check it )
 
Last edited:
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Usually the x-coordinate comes first and y second in the notation.
And check the spacing of the solutions in x, it is not pi/2.
 
mfb said:
Usually the x-coordinate comes first and y second in the notation.
And check the spacing of the solutions in x, it is not pi/2.

Oops, I tried it correctly first but then swapped to see if that helped with anything, i put it back in x/y

But, i redid the problem and got..
y=0, x = (1/18)pi(4n-1)
y=0, x = (1/18)pi(4n+1)

Not sure how to translate that to the 4 closest points? Tried this but didn't work..

((1/18)pi(4-1),0), ((1/18)pi(0-1),0), ((1/18)pi(4+1),0), ((1/18)pi(0+1),0)
 
I don't know how powerful the automatic (?) system to check the points is. I would not try to feed it with calculations like that. Maybe it needs decimal numbers, maybe something like 3/18 pi is okay (but where is the point in things like "4-1"?
((1/18)pi(4+1),0) is not among the 4 closest points.
 
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mfb said:
I don't know how powerful the automatic (?) system to check the points is. I would not try to feed it with calculations like that. Maybe it needs decimal numbers, maybe something like 3/18 pi is okay (but where is the point in things like "4-1"?
((1/18)pi(4+1),0) is not among the 4 closest points.

Ah, thanks a bunch!
Solution:
((1/18)pi(3),0), ((1/18)pi(-1),0), ((1/18)pi(-3),0), ((1/18)pi(1),0)
 

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