Maximum Capacity of a Flat-Bottomed Rowboat

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Homework Help Overview

The problem involves determining the maximum capacity of a flat-bottomed rowboat before it swamps, given its dimensions and the weight of individuals. The subject area includes principles of buoyancy and density in fluid mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Archimedes' principle and the relationship between the weight of displaced water and the total weight of the boat and occupants. There are attempts to calculate the submerged volume and the corresponding weight limits.

Discussion Status

Some participants have provided calculations and interpretations of the problem, while others question the accuracy of provided answers and explore the implications of different interpretations regarding the number of people the boat can hold.

Contextual Notes

There is uncertainty regarding the inclusion of a rower in the weight calculations, and participants are considering whether the provided answer may contain an error or oversight.

enceladus_
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Homework Statement



A rectangular, flat-bottomed rowboat has a mass of 120 kg when empty. It's 3 meters long, 1 meter wide, and .24 meters deep. How many 85 kg people could it hold before swamping?


Homework Equations



d=m/v ?

The Attempt at a Solution



I need to determine the average density, then compare to the density of water. I know the density of water...I know this isn't that hard. I need the average density of the boat + x people.
 
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What volume of water is displaced just before swamping?
 
Remember Archimedes' principle? The buoyant force on the boat is equal to the weight of the water that is displaced by the boat. And the amount of water displaced by the boat is equal to the submerged volume of the boat. The submerged volume is l*w*x, where l*w = 3 m2, and x is the depth by which it is submerged. So, when x is equal to 0.24 inches, you start taking on water and you sink.

For it to be balanced (floating), the weight of the displaced water (buoyant force) has to be equal to the combined weight of the boat + people.

(density of water)*(l*w*x) = (weight of boat + people)
 
(3*1*.24)(1000 kg/m3) = 720 kg/m3

85 * 7 = 595 kg

595 + 120 = 715 kg

My answer is 7 people, but I know from the video that my answer is wrong...

Is the mass of the displaced fluid more than the mass of the object...
 
Last edited:
Your answer looks right to me.
 
The answer they have is:

"It could hold 6 people, 590 kg, not counting the boat."

Could they have messed up? 85 * 6 = 510 kg.
 
enceladus_ said:
The answer they have is:

"It could hold 6 people, 590 kg, not counting the boat."

Could they have messed up? 85 * 6 = 510 kg.
Maybe, or is it a matter of one rower and six passengers?
 
I don't think so. A rower is not mentioned in the problem. That is so weird though. I can't believe that there would be a mistake like that.
 
Sounds like either a typo or arithmetic error on the part of "them", whoever they are. After all, they got the. 590 kg part right.
 
  • #10
Thank you all very much. I appreciate your time and wisdom very much!:smile:
 

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