Maximum force that we can exert without breaking the rope?

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Homework Help Overview

The discussion revolves around a physics problem involving forces, specifically the maximum force that can be exerted on a block attached to a rope without breaking it. The block has a weight of 5N, and the rope can withstand a maximum of 20N.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the applied force, the weight of the block, and the maximum tension the rope can handle. Questions arise regarding the correct calculation of the applied force needed to ensure the net force remains within the rope's limits.

Discussion Status

There is an ongoing exploration of the problem, with some participants attempting to clarify the relationship between the forces involved. Multiple interpretations of the applied force are being discussed, but no consensus has been reached regarding the correct value.

Contextual Notes

Participants reference a test question related to this problem, indicating a potential constraint in the context of homework rules or specific expectations for the solution approach.

NeoPhoenix
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Homework Statement



If we want to pull a block with a weight of 5N attached to a rope that is just able to resist 20N. What is the maximum force that we can exert without breaking the rope? xD

Homework Equations



Fnet (in y) = ma = F (applied force) - W (weight)

The Attempt at a Solution



What I think is that: if the rope will just resist 20, and we already know that the weight of the block is 5N, then we should apply a 15N force right ?
 
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You want the net force to be less than or equal to 20N. Knowing W=5N, what is the applied force you should apply?
 


actually, this is a problem that I had on a test some days ago...I think that was the question in fact. What force I should apply ?...
 


NeoPhoenix said:
actually, this is a problem that I had on a test some days ago...I think that was the question in fact. What force I should apply ?...

The maximum net force is 20N, using your relevant equation, what would the applied force?
 


25n ?
 


NeoPhoenix said:
25n ?

That seems correct.
 


thanks xD
 

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