Finding Maximum Force for Sled Without Lifting

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SUMMARY

The maximum force that can be applied to a sled being pulled at a 25° angle without lifting it off the ground is determined by the balance of forces acting on the sled. Given the sled-passenger-rope mass of 80 kg and negligible friction, the equations of motion reveal that the vertical component of the pulling force must equal the weight of the sled for lift-off to occur. Specifically, when the pulling force F satisfies the equation Fsin(25°) = 9.8 * 80 kg, the sled begins to lift, indicating that the maximum force before lift-off is reached can be calculated using this relationship.

PREREQUISITES
  • Understanding of Newton's second law (sum of forces = ma)
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with force components in physics
  • Basic concepts of normal force and its role in lifting
NEXT STEPS
  • Calculate the maximum force using the equation F = (9.8 * 80 kg) / sin(25°)
  • Explore the implications of friction in sled dynamics
  • Investigate the effects of different angles on the maximum force required
  • Learn about the role of normal force in various pulling scenarios
USEFUL FOR

Physics students, educators, and anyone interested in understanding force dynamics in sled pulling scenarios will benefit from this discussion.

yitriana
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Homework Statement


A dog pulls a sled with unspecified force at 25° above horizontal. Mass of sled-passenger-rope partile is 80 kg and there is negligible friction. Find the maximum magnitude of force F that can be applied to the rope without lifting the sled off the surface.

Homework Equations


sum of forces = ma
normal force is Fn
mass of particle is m

The Attempt at a Solution



Fxnet = Fcos(25) = max
Fynet = Fsin(25) - 9.8*m + Fn

In any case where the sled is not lifted, Fynet = 0, since acceleration is in direction of x only (for this problem).

However, I am confused about how to find maximum force before sled is lifted.
 
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When you start to lift the sled you have: Fsin(25)= 9.8*m. In that moment, you have no Fn because the sled is not touching the ground.
 
Don't think of being lifted off the ground in terms of the net force, but in terms of the normal. When the normal is 0 or negative, then you have lift-off.

Though the two approaches are completely equivalent, I find that, personally, the latter is simpler to follow.
 

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