Maximum Height of model rocket

Click For Summary

Homework Help Overview

The problem involves determining the maximum height of a model rocket launched with an initial velocity of 55 m/s, described by the height function h(t) = -4.9t² + 55t. Participants are exploring how to find the maximum height based on this quadratic model.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between initial velocity and maximum height, questioning how to find the time at which the maximum height occurs. Some suggest substituting values for time to observe height changes, while others mention the derivative of the height function as a potential tool for analysis.

Discussion Status

There is an ongoing exploration of the problem, with participants offering insights into the derivative of the height function and its implications. Some have attempted to derive the maximum height and are seeking confirmation or more precise methods to express their findings.

Contextual Notes

Participants note the use of the quadratic formula in other contexts but express uncertainty about its applicability here. There is also mention of plotting the function to gain insights into its behavior.

DerekF
Messages
2
Reaction score
0

Homework Statement


A model rocket is launched with an initial velocity of 55 m/s. Its height as a function of time can be modeled by h(t) = -4.9t2 + 55t. Determine the maximum height reached by the rocket.

Homework Equations


h(t) = -4.9t2 + 55t

The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

I am not sure how to approach this problem though I assume it has something to do with the initial velocity since it is included in the question. The quadratic formula was used in another problem but it isn't applicable here as far as I can tell. It sounds like I need to find the maximum time or t, in order to be able to find the maximum height. If this isn't possible, would the correct thing be to substitute arbitrary values for time until the height is no longer increasing or positive? If not, I have absolutely no idea.

Any help would be great. Thank you.* Edit *

Following the logic above it seems like the maximum height would be approximately 153.6 metres after 6 seconds. If this is correct, is there a proper way to express this or find a more precise value for t?
 
Last edited:
Physics news on Phys.org
DerekF said:

Homework Statement


A model rocket is launched with an initial velocity of 55 m/s. Its height as a function of time can be modeled by h(t) = -4.9t2 + 55t. Determine the maximum height reached by the rocket.


Homework Equations


h(t) = -4.9t2 + 55t


The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

I am not sure how to approach this problem though I assume it has something to do with the initial velocity since it is included in the question. The quadratic formula was used in another problem but it isn't applicable here as far as I can tell. It sounds like I need to find the maximum time or t, in order to be able to find the maximum height. If this isn't possible, would the correct thing be to substitute arbitrary values for time until the height is no longer increasing or positive? If not, I have absolutely no idea.

Any help would be great. Thank you.


* Edit *

Following the logic above it seems like the maximum height would be approximately 153.6 metres after 6 seconds. If this is correct, is there a proper way to express this or find a more precise value for t?

Step 1: plot a graph of the function h(t), to see what is happening.
Step 2: translate the insights from your graph into a formal statement.
 
DerekF said:

Homework Equations


h(t) = -4.9t2 + 55t

The Attempt at a Solution



h'(0) = 55, since h'(t) = -4.9(0) + 55 = 55 <-- Height reached within time interval 0 - 1 s

The correct expression for the derivative of the height function is:

h'(t) = -9.8t + 55
 
SteamKing said:
The correct expression for the derivative of the height function is:

h'(t) = -9.8t + 55

Yeah, oops. I had that written down on paper but messed up here.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
Replies
2
Views
1K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K