Maximum impact parameter given effective potential

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SUMMARY

The discussion centers on the concept of capture in gravitational interactions as explained in David Morin's classical mechanics textbook. The key takeaway is that larger particle energies lead to capture due to the condition defined by the effective potential, specifically that the maximum effective potential \( V_{eff}^{max} \) must be less than or equal to the energy \( E \) of the particle. This relationship indicates that higher energies result in smaller impact parameters and reduced cross sections for capture, contradicting the initial intuition that lower energies would facilitate capture.

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  • Understanding of classical mechanics principles
  • Familiarity with effective potential concepts
  • Knowledge of angular momentum and energy relationships
  • Basic grasp of gravitational interactions
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  • Study the concept of effective potential in classical mechanics
  • Explore the relationship between angular momentum and energy in gravitational systems
  • Learn about impact parameters and their significance in particle capture
  • Review examples of gravitational capture scenarios in astrophysics
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Students of classical mechanics, physicists studying gravitational interactions, and anyone interested in the dynamics of particle capture in potential fields.

stephen8686
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This problem is from David Morin's classical mechanics textbook:
problem.PNG

I am having trouble with Part b. Here is the textbook's answer:
andswe.PNG


I do not understand why large particle energies lead to capture. I would think that smaller energies would lead to capture because the particle wouldn't have enough energy to escape the gravitational potential, whereas large energy particles could woosh past. If someone could explain why my intuition is wrong, that would be very helpful.
 
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How do you make out that larger energies lead to capture?
 
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PeroK said:
How do you make out that larger energies lead to capture?
That's what the answer says, "The condition for capture is therefore ##V_{eff}^{max}\leq E## " That is the part of the answer that I don't understand
 
stephen8686 said:
That's what the answer says, "The condition for capture is therefore ##V_{eff}^{max}\leq E## " That is the part of the answer that I don't understand
That condition resolves into a smaller impact parameter and smaller cross section for capture for greater energy.
 
stephen8686 said:
That's what the answer says, "The condition for capture is therefore ##V_{eff}^{max}\leq E## " That is the part of the answer that I don't understand
That equation in itself is about the relationship between angular momentum and energy. But, angular momentum increases with energy if other factors are held constant, so it doesn't say what you are thinking it says.
 

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