Maximum Likelihood Estimator for Exponential Density Function

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twoski
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Homework Statement



Given f(x;λ) = [itex]cx^{2}e^{-λx}[/itex] for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = [itex]x^{2}[/itex], du = 2xdx, dv = [itex]e^{-λx}[/itex] and v = [itex]-e^{-λx} / λ[/itex]

After a bit of work i end up with:

-c/λ [ [itex]x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0})[/itex] ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...
 
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twoski said:

Homework Statement



Given f(x;λ) = [itex]cx^{2}e^{-λx}[/itex] for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = [itex]x^{2}[/itex], du = 2xdx, dv = [itex]e^{-λx}[/itex] and v = [itex]-e^{-λx} / λ[/itex]

After a bit of work i end up with:

-c/λ [ [itex]x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0})[/itex] ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...

You have to integrate the second term from 0 to infinity, not just evaluate it. You'll need to integrate by parts again.
 
twoski said:

Homework Statement



Given f(x;λ) = [itex]cx^{2}e^{-λx}[/itex] for x ≥ 0

Determine what c must be (as a function of λ) then determine the maximum likelihood estimator of λ.

The Attempt at a Solution



So I'm supposed to integrate this from 0 to infinity, from what i can gather.

Let u = [itex]x^{2}[/itex], du = 2xdx, dv = [itex]e^{-λx}[/itex] and v = [itex]-e^{-λx} / λ[/itex]

After a bit of work i end up with:

-c/λ [ [itex]x^{2}e^{-λx}|_{0}^{∞} + 2( xe^{-λx}/λ |^{∞}_{0})[/itex] ]

What throws me off is that evaluating this leaves me with -c/λ( 0 ), which has to be wrong...

It might be easier to recognize that
[tex]x e^{-\lambda x} = - \frac{\partial}{\partial \lambda} e^{- \lambda x},[/tex]
and so forth.