MLE of P(X<2) - Exponential distribution

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SUMMARY

The discussion focuses on finding the Maximum Likelihood Estimator (MLE) of θ = P(X ≤ 2) for a random sample from an exponential distribution, specifically EXP(λ). The relevant equations provided include the probability density function f(x, λ) = λ e^(-λx) and the cumulative distribution function F(x, λ) = 1 - e^(-λx). The key insight is that to estimate θ, one must first recognize the relationship between the observed values and the exponential distribution, particularly how to derive the likelihood from the observed data.

PREREQUISITES
  • Understanding of exponential distribution and its properties
  • Familiarity with Maximum Likelihood Estimation (MLE)
  • Knowledge of probability density functions (PDF) and cumulative distribution functions (CDF)
  • Basic calculus for evaluating integrals
NEXT STEPS
  • Study the derivation of MLE for exponential distributions
  • Learn how to compute likelihood functions from observed data
  • Explore the relationship between MLE and cumulative distribution functions
  • Investigate applications of MLE in statistical inference
USEFUL FOR

Statisticians, data scientists, and students studying statistical inference, particularly those focusing on maximum likelihood estimation in the context of exponential distributions.

SandMan249
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Homework Statement



Find the MLE of θ = P (X≤ 2) in a random sample of size n selected from an exponential distribution EXP(λ)

Homework Equations



f(x, λ) = λ e^(-λx)
F(x, λ) = 1 - e^(-λx)

The Attempt at a Solution


I know how to find the MLE of the mean of an exponential distribution. But I am not sure how I can tackle this problem.

We know that P ( X≤ 2) = ∫f(x) 0,2 = F(4)

How do I get to the Likelihood from here?

Thanks!
 
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SandMan249 said:

Homework Statement



Find the MLE of θ = P (X≤ 2) in a random sample of size n selected from an exponential distribution EXP(λ)

Homework Equations



f(x, λ) = λ e^(-λx)
F(x, λ) = 1 - e^(-λx)

The Attempt at a Solution


I know how to find the MLE of the mean of an exponential distribution. But I am not sure how I can tackle this problem.

We know that P ( X≤ 2) = ∫f(x) 0,2 = F(4)

How do I get to the Likelihood from here?

Thanks!

Is the following statement of your problem correct? You observe n independent values of X and observe that m of them have {X < 2} (or {X <= 2}). From that, you want to estimate θ = P{X <= 2}. If that is truly the statement, what does the exponential distribution have to do with it? (Of course, if you want to estimate λ you need to know the distribution, but that is not what you said you want to estimate.)

RGV
 

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