Why is the maximum bending moment at the center w(l^2) /8?

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SUMMARY

The maximum bending moment at the center of a uniformly distributed load (UDL) beam is calculated as w(l2)/8, where 'w' represents the load per unit length and 'l' is the length of the beam. This value arises from the algebraic sum of moments on one side of the section, which must be equal to the moment calculated on the opposite side, ensuring equilibrium. The distinction between hogging and sagging effects is crucial, as it influences the sign conventions used in calculations. Misunderstandings regarding these conventions are common, highlighting the importance of clarity in engineering principles.

PREREQUISITES
  • Understanding of bending moment theory in structural engineering
  • Familiarity with static equilibrium conditions
  • Knowledge of sign conventions in mechanics
  • Ability to analyze uniformly distributed loads (UDL)
NEXT STEPS
  • Study the derivation of bending moment formulas for beams under various loading conditions
  • Learn about shear force diagrams and their relationship to bending moments
  • Explore different sign conventions used in structural analysis
  • Investigate the practical applications of bending moment calculations in engineering design
USEFUL FOR

Structural engineers, civil engineering students, and professionals involved in the design and analysis of beams and load-bearing structures will benefit from this discussion.

chetzread
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Homework Statement


upload_2016-7-5_9-53-9.png

why the maximum bending moment at the center is w(l^2) /8 ?

Homework Equations

The Attempt at a Solution


shouldn't it be = 0 ?
when we take the moment about the center , the reaction force at the left will generate clockwise moment , while the reaction force at the right will generate antoclockwise moment , they will cancel out each other , resulting the moment = 0? Am i right ?[/B]
 
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chetzread said:

Homework Statement


View attachment 102859
why the maximum bending moment at the center is w(l^2) /8 ?

Homework Equations

The Attempt at a Solution


shouldn't it be = 0 ?
when we take the moment about the center , the reaction force at the left will generate clockwise moment , while the reaction force at the right will generate antoclockwise moment , they will cancel out each other , resulting the moment = 0? Am i right ?[/B]
This is similar to another post of yours, to which I replied: What definition of Moment are you using? There are two possible definitions, each of which can be derived from the other. The one I prefer is that the bending moment at a section is the algebraic sum of the moments on ONE SIDE of the section. You have to have a sign convention that should yield the same moment, whether you take it to the left of the section, or to the right. That acts as a check on whether you have made a mistake. Another check is to use the alternative definition (the integral of the shear force diagram- which I don't prefer, because of the arbitrary constant.
 
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pongo38 said:
This is similar to another post of yours, to which I replied: What definition of Moment are you using? There are two possible definitions, each of which can be derived from the other. The one I prefer is that the bending moment at a section is the algebraic sum of the moments on ONE SIDE of the section. You have to have a sign convention that should yield the same moment, whether you take it to the left of the section, or to the right. That acts as a check on whether you have made a mistake. Another check is to use the alternative definition (the integral of the shear force diagram- which I don't prefer, because of the arbitrary constant.
i am using the first one (algebraic sum of the moments on ONE SIDE of the section.
 
When you 'take moments about a point', you will get a zero answer for a body in static equilibrium. If you take moments on ONE side of the section, you will get a non-zero answer which should be numerically the same as that algebraic sum on the OTHER side of the section - in this case w(l^2) /8. In using sign conventions, don't attribute a positive moment to a clockwise - anticlockwise- action. The important thing is whether the action is having a hogging effect, or a sagging effect. In your beam with udl, taking momets at the beam centre, the effect of the reaction is sagging, and the effect of the udl is hogging (from the point of view of someone standing underneath the beam). Sign conventions are a big problem that have no world-wide agreement, and plenty of misunderstandings are possible. With practice, the finer points will become clearer to you, and you should recognise that engineering theory is not always the same as engineering practice.

Reference https://www.physicsforums.com/threads/maximum-moment-at-the-center.877845/
 
pongo38 said:
When you 'take moments about a point', you will get a zero answer for a body in static equilibrium. If you take moments on ONE side of the section, you will get a non-zero answer which should be numerically the same as that algebraic sum on the OTHER side of the section - in this case w(l^2) /8. In using sign conventions, don't attribute a positive moment to a clockwise - anticlockwise- action. The important thing is whether the action is having a hogging effect, or a sagging effect. In your beam with udl, taking momets at the beam centre, the effect of the reaction is sagging, and the effect of the udl is hogging (from the point of view of someone standing underneath the beam). Sign conventions are a big problem that have no world-wide agreement, and plenty of misunderstandings are possible. With practice, the finer points will become clearer to you, and you should recognise that engineering theory is not always the same as engineering practice.

Reference https://www.physicsforums.com/threads/maximum-moment-at-the-center.877845/
to be exact , my idea is anticlockwise moment = clockwise moment...So total moment =0 , the object in equilibrium...

in this thread
https://www.physicsforums.com/threads/moment-of-beam.877859/#post-5513296
I think it should be EIy" = 0.5Px -P(x-0.5L) -0.5P(L-x) ,that's why ihave the additional -0.5P(L-x) , is it true?
 
pongo38 said:
When you 'take moments about a point', you will get a zero answer for a body in static equilibrium. If you take moments on ONE side of the section, you will get a non-zero answer which should be numerically the same as that algebraic sum on the OTHER side of the section - in this case w(l^2) /8. In using sign conventions, don't attribute a positive moment to a clockwise - anticlockwise- action. The important thing is whether the action is having a hogging effect, or a sagging effect. In your beam with udl, taking momets at the beam centre, the effect of the reaction is sagging, and the effect of the udl is hogging (from the point of view of someone standing underneath the beam). Sign conventions are a big problem that have no world-wide agreement, and plenty of misunderstandings are possible. With practice, the finer points will become clearer to you, and you should recognise that engineering theory is not always the same as engineering practice.

Reference https://www.physicsforums.com/threads/maximum-moment-at-the-center.877845/
why can we only consider moment about a point at one side only?
 
That is the definition of bending moment. It's useful.
 

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