Maximum photocurrent ejected by electrons in photoelectric effect

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SUMMARY

The maximum photocurrent produced by ejected electrons in a photoelectric effect experiment can be calculated using the formula: photocurrent = (Power / Energy of the photon) * e, where e is the charge of an electron. In this discussion, a power of 28.0 mW and a photon energy of 3.06 eV were used, resulting in a maximum photocurrent of 9.1 mA. The wavelength of the incident light was determined to be 405 nm, and the stopping potential was noted as 1.45 V. The work function of the metal surface was calculated to be 1.61 eV.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Knowledge of photon energy calculations (E = hf)
  • Familiarity with the concept of stopping potential
  • Basic principles of electric current and charge (e)
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Mola
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Does anyone know how to determine the maximum photocurrent that could be produced by ejected electrons in a photoelectric effect experiment_(as unpolarized beam of light incidents on a metal surface)?
I don't know of any formula that calculates the photocurrent and I could not derive any. I was given Power as 28.0mW; frequency of the beam is 7.4* 10^14Hz; and stopping potential Vs as 1.45V.
- I calculated the wavelength of the beam of light as 405nm.(c/f);
- Energy in the photon as 3.06eV. (hf)
-Max speed of the electrons ejected as 7.1*10^5m/s. [sqrt(2K.E_max/mass)]
-Work function as 1.61eV. (E_photon - KE_max)

But I am not able to figure out a formula for determining the photocurrent.
Thanks.
 
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I have found the magic formula from someone. It's power divided by the Energy of the photon, and then multiplying that answer by e(charge of an electron). I ended up getting 9.1mA.
 

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