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Maximum potential of a sliding box down a hill

  1. Jul 23, 2008 #1
    1. Maximum potential of a sliding box down a hill
    1. A 150 kg box (with dimensions of 1.30 m on a side) sits at the top of a hill 4.35 m long angled at 30.0° to the horizontal. The box has 250 loops of wire wrapped around it. The loops lie in the plane of this paper. The box is allowed to slide down the hill, which has a coefficient of kinetic friction of 0.270. Once the box reaches the bottom of the hill, it slides along a horizontal frictionless plane, where it encounters a magnetic field produced by a 1.25 m long solenoid with 5000 loops and a current of 1.40 A running through it. The magnetic field points out of the page.
    a. What is the maximum potential produced in the wires wrapped around the box as it passes through the magnetic field? (The size of the field is large compared to the size of the box)
    b. In what direction does the induced current flow?
    c. If the wires have an internal resistance of 750 Ω, what is the maximum amount of induced current that flows through the loop?

    2. i dont understand what to do after this point

    150 kg
    n=250 loops
    B= out of the page
    n=5000 turns
    I=1.4 A

    B(horz)= (u(o) NI) / l
    B(horz)= [(4*pi*10^-7)(5000)(1.4A)]/1.25M
    B(horz)=0.00704 T
  2. jcsd
  3. Jul 23, 2008 #2


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    Welcome to PF!

    Hi fizix26! Welcome to PF! :smile:

    (are you the same person as melene?)

    Have you worked out the speed of the box when it reaches the horizontal plane? :smile:
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