Maximum Power Transfer for Z = 12+24 Ohms

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SUMMARY

The required load impedance for maximum power transfer when the source impedance is Z = 12 + 24 Ohms is ZL = 12 - 24 Ohms, which represents the complex conjugate of the source impedance. This conclusion is drawn from the principle that for maximum power transfer, the load impedance must match the complex conjugate of the source impedance. The discussion confirms this approach as correct, emphasizing the importance of considering both magnitude and phase in impedance matching.

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andytb1232000
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Homework Statement


Find the required value of the load to achieve maximum power transfer for Z = 12+24 ohms


Homework Equations



ZL = Zs

3. The Attempt at a Solution [/b

As the question does not state whether or not the phase or magnitude of the load can or cannot be varied. I believe the answer to be ZL= 12-24 ie the complex conjugate.
Does this seem correct?
 
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See http://www.allaboutcircuits.com/vol_1/chpt_10/12.html
 
andytb1232000 said:

Homework Statement


Find the required value of the load to achieve maximum power transfer for Z = 12+24 ohms


Homework Equations



ZL = Zs

3. The Attempt at a Solution [/b

As the question does not state whether or not the phase or magnitude of the load can or cannot be varied. I believe the answer to be ZL= 12-24 ie the complex conjugate.
Does this seem correct?


Yes.
 

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