Thevenin equivalent of circuit and maximum power transfer

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SUMMARY

The discussion focuses on finding the Thévenin equivalent of a circuit with an impedance of Z = 15 + j24 Ω and determining the load value for maximum power transfer. The calculated Thévenin voltage is V_{out} = 0.4167 V_{in} with a total impedance of Z_{total} = 0.67Z. For maximum power transfer, the optimal load impedance is Z_{load} = 10 - j16 Ω. The calculations and methodology presented are confirmed as correct by participants in the discussion.

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Homework Statement



Find the Thévenin equivalent of the circuit and the required value of the load for maximum power transfer for Z = 15 + j24 Ω.

Homework Equations



Voltage divider equation and Z_{in} = Z_{load} 'complex conjugate' for maximum power transfer.

The Attempt at a Solution



Thévenin equivalent:

Since there is no current flowing through 2.5Z:

V_{out} = V_{in} \times \frac{2 \parallel 5}{2 + (2 \parallel 5)} = 0.4167 V_{in}

Z_{total} = 0.67Z

Maximum power transfer:

Z_{load} = 0.67 \times (15-j24) = 10 - j16 Ω

Does this appear to be correct?
Thank you for anyone looking into that.
 

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