Maximum Slit width diffraction minima

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Homework Help Overview

The problem involves determining the maximum slit width for which no visible light exhibits a diffraction minimum, considering the wavelengths of visible light range from 400 nm to 750 nm.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between slit width and wavelength, questioning how to determine the appropriate wavelength to use when considering the range of visible light. There are attempts to clarify when diffraction minima occur and under what conditions they do not exist.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have suggested that the maximum slit width may relate to the smallest wavelength in the visible spectrum, while others are considering the implications of using different wavelengths. There is no explicit consensus yet.

Contextual Notes

Participants are grappling with the implications of using a range of wavelengths and how that affects the determination of the slit width. There is mention of specific values like 400 nm and 750 nm, but no resolution has been reached regarding the correct approach.

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Homework Statement



What is the maximum slit width so that no visible light exhibits a diffraction minimum?(Visible light has wavelengths from 400 nm to 750 nm.)


Homework Equations



D*sin(theta)=m*lambda ; where D = slit width,theta in degrees, m =1,2,3,..., and lambda is wavelength. The maximum slit width occurs at sin(90) =1 and if we take m=1 the equation reduces to D=lambda. When the slit width is equal to the wavelength of light passing through it then no diffraction minima are observed.

The Attempt at a Solution



For visible light, I just assumed that the maximum slit width had to be equal to the largest wavelength contained in visible light (750nm), but this does not make sense because then the wavelength at 450nm would still be defracted. I know for a fact that a slit width of 750nm is wrong, so I am guessing that the answer might be 450nm or maybe the average wavelength of visible light but am not sure

Any help is greatly appreciated.
 
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Minimum intensity occurs at [tex]\sin\theta_{min} = \frac{\lambda}{d}[/tex] .

So when is there no [tex]\theta_{min}[/tex]?
 
I guess my question is what wavelength do you use for visible light? It is a mixture of different wavelengths so How do I determine D when there are multiple wavelengths of light is it just the smallest wavelength (400) or the average...?
 
Decelerate said:
I guess my question is what wavelength do you use for visible light? It is a mixture of different wavelengths so How do I determine D when there are multiple wavelengths of light is it just the smallest wavelength (400) or the average...?

When does [tex]\theta_{min}[/tex] not exist?
 
zachzach said:
When does [tex]\theta_{min}[/tex] not exist?

When lambda is larger than d...I still don't really understand how that will help me determine the width for visible light from 400-750
 
Decelerate said:
When lambda is larger than d...I still don't really understand how that will help me determine the width for visible light from 400-750

So when [tex]d < \lambda , \theta_{min}[/tex] DNE. So if [tex]d = 700nm[/tex] what range does not have a minimum? What about if [tex]d = 600nm[/tex]?
 
I had to edit that fyi.
 
so i guess d has to be 400nm for the range of 400-750 to not have a minimum
 
Decelerate said:
so i guess d has to be 400nm for the range of 400-750 to not have a minimum

That is my guess as well, less than 400nm but yeah.
 
  • #10
Let me enter it in and see if it is right.
EDIT: yes 400nm is right
Thanks!
 

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