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## Homework Statement

Prove that the maximum speed (Vmax) of a mass on a spring is given by 2PifA

f=frequency

A=amplitude

## Homework Equations

ac=v^2/r

T=2Pir/v

ac=4 Pi^2 r / T^2

T=2Pi sqrt(r/ac) , T=2Pi sqrt(A/ac)

-x/a=m/k

T=2Pi sqrt(-x/ac) , T=2Pi sqrt(m/k)

f=1/2Pi sqrt(k/m) , f=1/2Pi sqrt(a/-x)

## The Attempt at a Solution

Ok so after much trial and failure and producing much gibberish full of variables..... This is what i know so far that is right, is the mass is going at max speed then the total energy which is made of potential energy plus kinetic energy, is all made of just kinetic energy because potential energy should equal 0 at max speed, well i think so....

Et=Ek

kA^2=mv^2

and anything after that doesn't make sense whatever route i try.

I am taking a correspondence course by ILC ( the independent learning centre at Ontario) , and its been 6 years since i graduated from high school so my grade 12 physics its not very good.

Thank you for all the help !!