Maximum speed of overdamped oscillator without crossing origin

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Homework Help Overview

The problem involves an overdamped oscillator characterized by its natural frequency and damping coefficient. The original poster seeks to determine the maximum initial speed towards the origin that the oscillator can have without crossing the origin, given that it starts at a positive position.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the general form of the position function for an overdamped oscillator and express uncertainty about how to derive the maximum initial speed based solely on the initial position.

Discussion Status

Some participants have provided their equations for the position function and are exploring the implications of these equations on the maximum speed. There is an ongoing inquiry into how to determine the initial speed and whether the oscillator crosses the origin.

Contextual Notes

Participants note the lack of specific values for the damping coefficient and natural frequency, which may affect the ability to derive a clear solution. There is also mention of the need to solve for coefficients in the position equation.

MeMoses
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Homework Statement


An overdamped oscillator with natural frequency w and damping coefficient g starts out at postion x0 > 0. What is the maximum initial speed towards the origin it can have without crossing the origin?


Homework Equations


x(t) for overdamped oscillator


The Attempt at a Solution


x(t) for a general overdamped oscillator has been solved already. However if I only know x0 > 0 and nothing else, how do I go about determining the maximum speed. I can't see how this problem will workout and I can't get it started. Thanks for any help
 
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Hi MeMoses! :smile:
MeMoses said:
x(t) for a general overdamped oscillator has been solved already. However if I only know x0 > 0 and nothing else, how do I go about determining the maximum speed. I can't see how this problem will workout and I can't get it started.

Just find the answer as a function of xo :wink:
 
Edit: My idea made no sense. So how do find this maximum v0?
 
Last edited:
MeMoses said:
Edit: My idea made no sense. So how do find this maximum v0?

what is your x(t) equation?
 
I get x(t) = Ae**((-g-z)t) + Be(-(g-z)t) with z=sqrt(g**2 - w**2). At t=0 I get x0 = A + B
 
Last edited:
Hi MeMoses! :wink:
MeMoses said:
I get x(t) = Ae**((-g-z)t) + Be(-(g-z)t) with z=sqrt(g**2 - w**2). At t=0 I get x0 = A + B

(hmm … I'm not sure how that's supposed to be read :confused: … but anyway …)

So what is the maximum value of x(t) (presumably at t = ∞) ?

And what is the intitial speed? :smile:
 
Sorry i type that from my phone. The lim x(t) as t approaches infinity is 0, it will always go to 0 eventually but how do I know if it crosses the origin or not and how can I find the initial speed using what you told me? Edit: also how can I solve the coefficients?
 
Last edited:

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