Maximum speed Tarzan can tolerate

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SUMMARY

The maximum speed Tarzan can tolerate at the lowest point of his swing is 9.17 m/s, calculated using the force exerted by his arms (1.4 x 10^3 N) and his mass (80 kg). Initially, an incorrect application of the formula v=(2pi*r)F led to an unrealistic speed of 42,202 m/s. The correct approach involved using Newton's second law (F=ma) to find acceleration and then applying centripetal acceleration (a=v^2/r) to derive the maximum speed.

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  • Understanding of Newton's second law (F=ma)
  • Knowledge of centripetal acceleration (a=v^2/r)
  • Basic algebra for solving equations
  • Familiarity with units of force, mass, and speed
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  • Study the application of Newton's laws in dynamic systems
  • Learn about centripetal motion and its equations
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Homework Statement



Tarzan plans to cross a gorge by swinging in an arc from a hanging vine. If his arms are capable of exerting a force of 1.4x10^3 N on the vine, what is the maximum speed he can tolerate at the lowest point of his swing? His mass is 80kg and the vine is 4.8m long.

Homework Equations



F=ma
v=(2pi*r)F

The Attempt at a Solution



I used the second equation to find v and ended up with 42,202 m/s, which seems way too high. I'm doubting this was the right equation to use since I didn't insert mass, and I'm not sure if 4.8m is the radius.
 
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Nevermind, I redid the problem and it makes much more sense now.
I used f=ma, then a= F/m and got a= 17.5m/s^2. Then I used a=v^2/r and got v= 9.17m/s.
 

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