Maximum Velocity for collision given acceleration

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SUMMARY

The discussion focuses on calculating the maximum velocity a car can travel without colliding with an obstacle, given an initial speed of 30.0 m/s, a reaction time of 0.150 seconds, and a braking acceleration of -3.50 m/s². The key equations used include the kinematic equations for motion: \(d = Vi \cdot t + \frac{1}{2} a \cdot t^2\) and \(Vf^2 = Vi^2 + 2 \cdot a \cdot d\). The challenge arises from the introduction of multiple variables, which complicates the setup of the equations. The solution requires careful consideration of both the reaction distance and braking distance to determine if a collision occurs.

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Tearsandrille
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Homework Statement


You are driving a car going 30.0m/s; suddenly you see a scary monster 130.0 m ahead. It takes you 0.150s to react before applying the brakes, and the average acceleration during the breaking is 3.50m/s^2.
a. Determine if you hit the monster?

b. What maximum speed could you travel and not hit the monster?


Homework Equations


v = d/t
d = Vi*t + 1/2*a*t^2
Vf^2 = Vi^2 + 2*a*d

The Attempt at a Solution


I know that d1 (my reaction time distance) and d2 (my braking distance) must equal 130.0m.
I tried setting it up this way, but then I have two variables:
130m = Vi*0.150s + Vi*t + 1/2*(-3.50m/s^2)*t^2

It seems everything I try to set up is giving me two unknown variables!

Thanks in advance for help,
TS
 
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Hi Tearsandrille! :smile:

(try using the X2 icon just above the Reply box :wink:)
Tearsandrille said:
d = Vi*t + 1/2*a*t^2
Vf^2 = Vi^2 + 2*a*d

It seems everything I try to set up is giving me two unknown variables!

That's because you introduced an unasked-for variable (t) …

try using your other equation! :wink:
 

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