Maximum velocity of charged particles

[Knfoster]

Homework Statement

A particle, with a charge +q and a mass, m, is inserted into an evacuated chamber. The chamber is placed between two parallel metal plates that are a distance d apart, and are connectd to the terminals of a power supply that provide V volts (one plate to the positive terminal and one plate to the negative terminal.)

A. What is the maximum velocity that the field could give to the particle when the chamber is constructed so that the sides connecting the plates are insulating?

B. What is the maximum velocity that the field could give to the particle when the chamber is constructed so that the sides connecting the plates are good conductors?

Homework Equations

F=k*(q1*q2)/(d^2^)
[I'm not sure if this is what I need or not?]

The Attempt at a Solution

Would the velocity of the insulating plates be zero, since they don't allow charged particles to move through them?

I could use some help please. Thanks!

 

[rl.bhat]

Inside the box made up of metal, there will be no electric field. So the charged particle will not experience any force.
In the insulated box KE acquired by the charged particle is equal to q*V = 1/2*m*v^2

 

[kerimek]

I would like to clarify that the maximum velocity of charged particles in this scenario is not dependent on the material of the sides connecting the plates. It is determined by the voltage applied to the plates and the mass and charge of the particle. The equation you provided, F=k*(q1*q2)/(d^2), is the Coulomb's law, which calculates the force between two charged particles. In this case, the force acting on the particle is equal to its mass multiplied by its acceleration. Therefore, using the equation F=ma, we can rearrange it to solve for the maximum acceleration, a, which is equal to the maximum velocity, v, divided by the distance between the plates, d. So the maximum velocity of the particle can be calculated using the equation v=√(2qV/m), where V is the voltage applied to the plates. This equation applies to both insulating and conducting sides connecting the plates, as the force acting on the particle is still the same. I hope this helps clarify your understanding.