MCNPX - How calculate Kerma (kinetic energy released per unit mass) in Air?

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SUMMARY

This discussion focuses on calculating Kerma in air using MCNPX version 2.7 for a project involving mean glandular dose (MGD) in women with augmented breasts. The user, Alexander, is encountering difficulties obtaining accurate Kerma values, specifically reporting low results when using the F6 tally for energy deposited in the air block. Key insights include the necessity to multiply the F6 results by the photon flux to convert MeV/g to Gy/s, as well as the importance of ensuring the SDEF card is correctly configured for the desired beam geometry.

PREREQUISITES
  • Understanding of MCNPX 2.7 simulation software
  • Knowledge of Kerma and its calculation in radiation physics
  • Familiarity with tally types in MCNPX, specifically F6 for energy deposition
  • Basic principles of photon flux and its role in dose calculations
NEXT STEPS
  • Review the MCNPX user manual for detailed explanations of the SDEF card configuration
  • Learn about the relationship between photon flux and dose calculations in radiation therapy
  • Investigate methods for normalizing MCNPX results to obtain accurate Kerma values
  • Explore advanced MCNPX tally techniques for improved simulation accuracy
USEFUL FOR

This discussion is beneficial for radiation physicists, medical physicists, and students involved in dosimetry and radiation therapy, particularly those using MCNPX for simulations related to breast cancer treatment.

Alexander Camargo
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Hi, my name is alexander, i am student from Institute of radioprotection and dosimetry (IRD). My project is calculate MGD (mean glandular dose) from womans with augmented breast. i am having dificulties to calculate Kerma in air with mcnpx. I drew a block of air above the breast, i am using the "tally" f6 (energy deposited in cell) for obtain the kerma in MeV/g. However, I'm not obtained good results, i obtain very low values.

I ask for help for ideas or suggestions.

thanks.
 
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Hi,
Can you put your file (in ascii) ?
 
mcnpx 2.7

Code:
C Alexander Camargo - 23/10/2018
C *******************Celulas********************************
10 2 -1.090 (-1 2 -3 4) #20 imp:p=1 VOL=149.2256511   $ espessura / thickness                     
20 1 -0.9850 (-5 6 -7 8) imp:p=1 VOL=353.4291735           $ mama / breast 
30 3 -0.001205 (-10 -11 12 13) #10 #20 imp:p=1 VOL=10.3059947 $ ar / air
C ----- Acompanhamento -----
80 3 -0.001205 (-80) #10 #20 #30 imp:p=1                   $ Mundo-Interno / universe
90 0 (80) imp:p=0                                          $ Fim do Acompanhamento

C -------------Geometrias / geometries ----------------
C ------------ espessura / thickness ----------
1 cz 8
2 pz -2.5
3 pz 2.5
4 px 0
C ------------ mama / breast -------------
5 cz 7.5
6 pz -2
7 pz 2
8 px 0.5
C ------------ AR / air -------------
10 cz 8.1
11 pz 2.6
12 pz 2.5
13 px 0
C --- Fim de Acompanhamento / universe ---
80 SO 225 $ Mundo

C area 0 0 0 0 0 0 0 0 0 0 100.5312 0 0 0
mode P $ fotons / photons
C -------------- fonte e energia (monoenergetico) ----------------
sc1  raio x monoenergetico para mamografia                               
SDEF X=d1 Y=d2 Z=60 PAR=2 ERG=0.018 VEC=0 0 1 DIR=-1
SI1 -1 9 $ sampling range Xmin to Xmax
SP1 0 1 $ weighting for x sampling: here constant
SI2 -10 10 $ sampling range Ymin to Ymax
SP2 0 1 $ weighting for y sampling: here constant
C                                                           
C **************************** Materiais *********************************                               
C ***************************** mama padrao 50/50 **********************************   
m1    1000          -0.1140  $ H
      6000          -0.5250  $ C
      7000          -0.0060 $ N
      8000          -0.3535 $ O
      11000         -0.0005  $ Na
      16000         -0.0005 $ S
      17000         -0.0005  $ Cl
C                                                                           
C ------------------------ Pele -------------------------------
m2    1000          -0.100  $ H
      6000          -0.199  $ C
      7000          -0.042 $ N
      8000          -0.650 $ O
      11000         -0.002  $ Na
      15000         -0.001  $ P
      16000         -0.002 $ S
      17000         -0.003  $ Cl
      19000         -0.001 $ K
C
C ****************************** AR ***************************************     
m3    6000           -0.000124   $ C
      7000           -0.755268   $ N
      8000           -0.231781   $ O
      18000          -0.012827   $ Ar
C
C ************************** Tungstenio *********************************
C m4    74000          -1.000
C
C *************************************************************************
C
C                               
C ***************************** Tallies ***********************************
f4:p 30
f6:p 30
c
C
C
C
C *************************** tempo de Input **********************************     
NPS   16000000   $ Stop after XX source particles have been run.               
C CTME 120          $ Stop run after XX minutes.
 
Last edited by a moderator:
I don't see a trivial error.
I suppose you have multiplied F6 by 1.602e-10 to convert in Gy. Remember that to compare results, you have to normalize to the fluence (K/phi) to obtain Gy.cm2.

Note that for me the "SDEF" is Strange. If you want a rectangular parallel beam you must write something like that "SDEF X=d1 Y=d2 Z=0 pos 0 0 60 …" but in fact I don't know what you want to simulate ...
 
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upload_2018-10-24_12-36-30.png


i need to kerma in air, but, i found very low results. I need multiplicate my results per 16000000 to found the valor?

I want simulate a mamography machine with focal point the 60cm the breast. My card "SDEF" is configured for a one-dimensional collimated beam in direction the -z axis.

sorry for my lack of knowledge, I'm new to the mcnpx area and I'm in the third year of graduation.
 

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Hi,
No ! A F6 result is in MeV/g for one photon emitted
If you want in Gy you have (F6)*1E6 (eV/g)*1E3 (eV/kg)*1.602E-19 (J/kg=Gy)=F6*1.602e-10 in Gy
But you must remember that MCNP normalizes the results to one photon. So you must multiplied by the photon flux (photon/s) to have a result in Gy/s.

For geometry I am not sure to understand. Do you want to simulate a beam like this :

upload_2018-10-24_21-4-17.png

and

upload_2018-10-24_21-5-38.png


Furthermore a mamography device not emitted a monocinetic energy of photon. For example :
c00069_f069-001-9780702042959.jpg


In first approximation a photon of 18 keV like in your simulation could be ok.
Hope it's help
 

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Thank you so much, you helped me a lot.

I understood everything your said, but, when I multiply my results in mev / g by 1.602E-10, I get very low results for what I want.

In cell 30 (semi-circular cylinder of air. to obtain kerma in air) i obtained = 6.01751E-05 (mev/g per history). multiplyed by 1,602E-10 i obtain 9,64E-15 (Gy por history).

my fluence obtained in cell 30 is 4.41740E-03 (1/cm**2)

I simulate one million histories. 4.867E+06 histories/minute.

please, help me in this question.
 
Your result is 9.64E-15 Gy for one Xrays emitted by your device.
You must known the flux of your device in Xrays/s and multiplied the flux by your results and you have Gy/s
 

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