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## Homework Statement

Consider a gaussian graph

let 5 quares on y -axis represent 1units

## Homework Equations

is it correct for me to say that the average value of the quantity on the y-axis is given by

y_av = (y_min + y_max) / 2

where y_min is smallest value of y in the graph = 0

y_max is the maximum value of y in graph = 2.4

average value of y, y_av = (0 + 2.4) /2 = 1.2

## The Attempt at a Solution

then, to find the area under graph, i use

area = y_av * (3 - -3) = y_av * 6 = 7.2

is this correct or wrong. in the above, i have all the things that i would if this was a question.

am i missing an assumption. the answer seems correct but is the method correct.

note that at this a-level, i don't have to know equation of gaussian graph nor do i do integration.

is this the correct way to find area under graph for non-linear graphs?? is there a general formula (not integration) for lower levels?