Consider a gaussian graph
let 5 quares on y -axis represent 1units
is it correct for me to say that the average value of the quantity on the y-axis is given by
y_av = (y_min + y_max) / 2
where y_min is smallest value of y in the graph = 0
y_max is the maximum value of y in graph = 2.4
average value of y, y_av = (0 + 2.4) /2 = 1.2
The Attempt at a Solution
then, to find the area under graph, i use
area = y_av * (3 - -3) = y_av * 6 = 7.2
is this correct or wrong. in the above, i have all the things that i would if this was a question.
am i missing an assumption. the answer seems correct but is the method correct.
note that at this a-level, i dont have to know equation of gaussian graph nor do i do integration.
is this the correct way to find area under graph for non-linear graphs?? is there a general formula (not integration) for lower levels?