Measuring distance using Ek and Ep?

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SUMMARY

The discussion focuses on calculating the distance a car travels while moving uphill using kinetic energy (Ek) and gravitational potential energy (Ep). The car, weighing 1 tonne and traveling at 75 km/hr, has a calculated kinetic energy of 36,450,000 Joules. By equating this energy to the gravitational potential energy formula, the height (H) the car can ascend is determined to be approximately 3719.38 meters. The calculations emphasize the importance of consistent units, particularly converting speed from km/hr to m/s.

PREREQUISITES
  • Understanding of kinetic energy formula: Ek = 0.5 * m * v^2
  • Knowledge of gravitational potential energy formula: Ep = m * g * h
  • Ability to convert units, specifically from km/hr to m/s
  • Basic physics concepts related to energy conservation
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  • Learn about unit conversion techniques, especially for speed and energy
  • Explore the principles of energy conservation in physics
  • Study the effects of incline on kinetic and potential energy
  • Investigate real-world applications of energy calculations in automotive physics
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Students studying physics, automotive engineers, and anyone interested in energy calculations related to motion and incline.

Clef
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measuring distance using Ek and Ep??!

okay, so the problem gives the following information
a car(1 tonne) is traveling at 75km/hr, up a hill. Assuming gravity is 9.8ms-2 , how far will the car travel?

so far I've done:
Ek= (.5 x m x v^2)
Ek= 36450000J

36450000=m x g x h
36450000=9800 x H
36450000/9800= H
H= 3719.38m

is this correct?
 
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It would help if one shows the substitution of the values.

1/2 mv2 = 0.5 * 1000 kg * (______ m/s)2? Make sure units are consistent.
 

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