Measuring of electrode potential.

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SUMMARY

The discussion centers on the measurement of electrode potential using a voltmeter in a circuit with two half-cells. Participants clarify that a voltmeter, despite its high resistance, does not create an open circuit; instead, it closes the circuit and measures potential difference by calculating current through a known resistance (V=RI). The conversation emphasizes the importance of understanding potential difference and circuit behavior in physics, rather than chemistry, to grasp how voltmeters function in these setups.

PREREQUISITES
  • Understanding of electrode potential and redox reactions
  • Knowledge of voltmeter operation and circuit theory
  • Familiarity with Ohm's Law (V=RI)
  • Basic concepts of electrical resistance and current flow
NEXT STEPS
  • Research the principles of voltmeter operation and its impact on circuit behavior
  • Study the concept of potential difference and its relation to charge
  • Explore the role of resistance in electrical circuits
  • Review general physics textbooks that cover circuit theory and measurement techniques
USEFUL FOR

Students and educators in physics and chemistry, electrical engineers, and anyone interested in understanding the principles of measuring electrical potential in circuits.

chewchun
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In set-up with two half-cells and a voltmeter, the potential difference is measured using the voltmeter.
But voltmeter has high resistance,which i know is still able to measure potential difference,but wouldn't it prevent electrons from flowing
What i meant was,the use of voltmeter creates a 'open circuit' which prevents electron flow and hence reaction in the two half cell will not take place?
But my teacher says that reaction takes place in both half cell,which meant that there is electron transfer and redox??
Does this have to do with some physics regarding voltmeter??
 
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Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
 
Borek said:
Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
So the high resistance of voltmeter must play a role.what if there is no voltmeter,for instance just a strip wire...is experiment the same?
Btw wouldn't the high resistance prevent current from flowing or something like that??
 
Please read how voltmeter works and how it measures the potential difference, your questions are directly answered by the theory behind it. Most likely any general physics book will do.

You can't understand potential measurement without good understanding what a potential difference is and how it is related to the charge, and what happens when you close the circuit - that's all physics.
 

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