Measuring of electrode potential.

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Discussion Overview

The discussion revolves around the measurement of electrode potential using a voltmeter in a set-up with two half-cells. Participants explore the implications of using a voltmeter on the electron flow and the reactions occurring in the half-cells, questioning the nature of the circuit when a voltmeter is included.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether the use of a voltmeter creates an open circuit that prevents electron flow and thus inhibits the reactions in the half-cells.
  • Another participant asserts that the voltmeter closes the circuit and measures current through a known resistance, suggesting that it does not leave the circuit open.
  • There is a discussion about the role of the voltmeter's high resistance and its effect on current flow, with one participant wondering about the outcome if a simple wire were used instead of a voltmeter.
  • A later reply emphasizes the importance of understanding how a voltmeter works and its relation to potential difference, suggesting that foundational physics knowledge is necessary to grasp these concepts.

Areas of Agreement / Disagreement

Participants express differing views on whether the voltmeter affects the circuit's operation and the reactions in the half-cells. The discussion remains unresolved, with multiple competing perspectives on the role of the voltmeter.

Contextual Notes

Participants reference the need for a deeper understanding of potential difference and circuit behavior, indicating that assumptions about the voltmeter's function and its impact on the circuit may not be fully explored.

chewchun
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In set-up with two half-cells and a voltmeter, the potential difference is measured using the voltmeter.
But voltmeter has high resistance,which i know is still able to measure potential difference,but wouldn't it prevent electrons from flowing
What i meant was,the use of voltmeter creates a 'open circuit' which prevents electron flow and hence reaction in the two half cell will not take place?
But my teacher says that reaction takes place in both half cell,which meant that there is electron transfer and redox??
Does this have to do with some physics regarding voltmeter??
 
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Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
 
Borek said:
Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
So the high resistance of voltmeter must play a role.what if there is no voltmeter,for instance just a strip wire...is experiment the same?
Btw wouldn't the high resistance prevent current from flowing or something like that??
 
Please read how voltmeter works and how it measures the potential difference, your questions are directly answered by the theory behind it. Most likely any general physics book will do.

You can't understand potential measurement without good understanding what a potential difference is and how it is related to the charge, and what happens when you close the circuit - that's all physics.
 

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