Measuring Torque of a Stepper Motor Using a Suspended Weight Method

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SUMMARY

This discussion focuses on measuring the torque of a stepper motor using a suspended weight method. The proposed method involves suspending a weight from the motor and measuring the displacement of the string after one full revolution, with torque calculated as τ = mgΔL. Participants clarified that the moment arm, defined by the shaft radius, is crucial for accurate torque measurements, and suggested using a larger radius to simplify calculations. The average torque can be approximated using τave = (mgΔL)/(2Nπ), where N is the number of turns.

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  • Understanding of torque calculations, specifically τ = F x d
  • Familiarity with basic physics concepts such as force, mass, and gravity
  • Knowledge of angular measurements and their application in rotational dynamics
  • Ability to use basic measuring tools like rulers and protractors
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  • Research the impact of moment arm length on torque calculations
  • Learn about the principles of rotational dynamics and torque measurement techniques
  • Explore methods for improving measurement accuracy, such as using a spool or spring scale
  • Investigate the relationship between stepper motor velocity and torque output
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Engineers, hobbyists, and students involved in robotics or motor control who need to measure and understand the torque characteristics of stepper motors.

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1. The problem statement, all variables and given/known data

I am trying to experimentally measure the torque of a stepper motor at various velocities. I'm not quite sure how this should be done. Here is a diagram of my proposed method so far:

259uxro.jpg

Basically a weight is to be suspended from the motor by a string, and I will measure by how much the string has moved up after one full revolution. Then I believe the torque must be: ##\tau = m \times g \times \Delta L##. Is this a correct method?

Homework Equations



Torque = Force x Distance

The Attempt at a Solution



I would greatly appreciate it if someone could confirm whether this is a correct method to get a roughly correct measurement of torque (within perhaps ~80% of the manufacturer quotedvalue at a given velocity)?

Do I need to take the shaft diameter into account (or perhaps some other factors)? What is the simplest way of doing this? :confused:
 
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Torque = Force x Distance
... sort of: the "distance" in question cannot be any old distance - it has to be the length of the moment arm. In your equation ##mg\Delta L## is the work, ##W=Fd##, not the torque.

The equivalent relation for rotation is ##W=\tau\theta## ... where the angle is in radians.
 
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Another way to measure the torque is to mount the motor on a pivot so the case can rotate (within limits), attach an arm to it with some sort of spring scale on the end.
 
Also in your diagram the Moment Arm - is the radius of the shaft ( from the center to where the string contacts it- so pretty small) -- so you can decrease the needed weight but adding a wheel/spool to the shaft to increase the radius. By choosing a good radius it will make the calculations easier ( e.g. if you want In*Lbs as units- use a 1" radius wheel)
 
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Thank you Simon, CWatters, Windadct for your responses. I'm still a bit confused.

So, basically, I must measure the radius and use ##\tau= mg \times r##, OR find the angle and use ##\tau = (mg \Delta L)/\theta##?

When the motor turns the string will be wound around the stepper motor shaft, and I must measure the shaft radius with string around it (the amount of string is supposed to change by a minuscule amount whenever I change the speed). I think this would be a very difficult and inaccurate way of measuring ##\tau##...

In the diagram below I have indicated ##\theta##:

i1mpht.jpg


Is this the right idea? This angle can be measured with a protractor. Even if the string is wound several times and we get the same θ, ΔL would be different. Therefore we get different torques each time. So is this a correct method?

P.S. Unfortunately I do not have access to an appropriate spool, or a spring scale at the moment. I have to work with only a ruler and a protractor.
 
Neglecting energy that goes to turn the motor components: $$\tau_{ave} = \frac{mg\Delta L}{2N\pi}$$ would be a reasonable approximation.
Notice that's an average for N entire turns. Picking a big value for N will probably be best.

##\vec \tau = \vec F_g\times \vec r \implies \tau=mgr## ...where r is the radius of the shaft, would be the torque exerted by gravity.
Since the stepper motor accelerates around one turn, it must be providing more torque than that.
 
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Thank you for the explanation Simon. It's all clear now. :)
 

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