Mechanical Advantage of a Lever

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Homework Help Overview

The discussion revolves around the concept of mechanical advantage in levers, specifically addressing a scenario where the mechanical advantage is 0.5. Participants are exploring the implications of this value on input force and the relationship between force and distance in lever systems.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning whether a mechanical advantage of 0.5 indicates that the input force is halved rather than amplified. There is also an exploration of the relationship between force and distance in the context of levers, with some participants suggesting that if force is halved, distance must be doubled.

Discussion Status

The discussion is active, with participants reiterating the initial question and engaging in reasoning about the implications of mechanical advantage. There is a suggestion to consider practical experimentation with levers to further understand the concepts being discussed.

Contextual Notes

Participants are encouraged to explore the definitions and implications of terms such as "distance" in the context of levers, indicating a potential gap in understanding that may need to be addressed.

Wolfowitz
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Homework Statement


If a lever has a mechanical advantage of 0.5 - does this mean the input force is not amplified but halved?


Homework Equations





The Attempt at a Solution

 
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wolfowitz said:

Homework Statement


if a lever has a mechanical advantage of 0.5 - does this mean the input force is not amplified but halved?


Homework Equations





The Attempt at a Solution


yes !
 
If a lever has a mechanical advantage of 0.5 - does this mean the input force is not amplified but halved?
So you might wonder, "What's the advantage then, when I have to exert double the force?" Well, as is the way with simple levers, if one thing halves, something else will double. Can you figure out how we benefit here, with this type of lever?
 
Work input = Work output
(Force * distance) input = (Force * distance) output
(Force * distance) input = (force/2 * distance2) output

Distance is doubled, right?

But what, exactly, is "distance" in terms of a lever?
 
Wolfowitz said:
Work input = Work output
(Force * distance) input = (Force * distance) output
(Force * distance) input = (force/2 * distance2) output

Distance is doubled, right?

But what, exactly, is "distance" in terms of a lever?

Make one using a ruler or stick, and see if you can figure it out.
 

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