A car, of mass 1100 kg, is traveling down a hill, inclined at an angle of 5o to the horizontal. The driver brakes hard and skids 15 m. The coefficient of friction between the tyres and the road is 0.7. Find the initial kinetic energy and speed of the car.
work done = force x displacement
weight of car down the hill = 1100 x 9.8 x sin 5o
normal reaction of road with car = 1100 x 9.8 x cos 5o
friction force = 0.7 x 1100 x 9.8 x cos 5o
The Attempt at a Solution
I really do not know how to go about solving this. This braking hard and skidding has stumped me.