Mechanical enery equation to valve equation

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SUMMARY

The discussion focuses on deriving the algebraic link between the mechanical energy equation and the valve equation, specifically the flow coefficient equation represented as Cv=Q * √(Sg/Δp). The user is writing a bachelor thesis on valves and seeks assistance in understanding this derivation using field units (American units). Key insights include the relationship between pressure as energy per unit volume and the expression ΔP = Q²ρ/Cv, which indicates energy loss per unit volume. The derivation is suggested to be based on Bernoulli's principle, neglecting elevation differences and assuming constant velocity.

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  • Understanding of Bernoulli's principle
  • Familiarity with flow coefficient equations
  • Knowledge of pressure drop calculations in fluid dynamics
  • Basic algebraic manipulation skills
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  • Study the derivation of the flow coefficient equation Cv=Q * √(Sg/Δp)
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Fingon
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Hi

I’m writing my bachelor thesis about valves, and was wondering if anyone could help me with the following derivation:
I need to show the algebraic link between the mechanical energy-equation and the ”valve equation” that is Cv=Q * [Square](Sg/[Delta]p). This can also be called the flow coefficient-equation.

Everything in field units (american units)

All help will be appreciated a lot!
 
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Fingon said:
Hi

I’m writing my bachelor thesis about valves, and was wondering if anyone could help me with the following derivation:
I need to show the algebraic link between the mechanical energy-equation and the ”valve equation” that is Cv=Q * [Square](Sg/[Delta]p). This can also be called the flow coefficient-equation.

Everything in field units (american units)

All help will be appreciated a lot!
Pressure is energy / unit volume so the [itex]\Delta P = Q^2\rho/C_v[/itex] expresses an energy loss per unit volume.

AM
 
Derive it from Bernoulli's. As the length of the valve is generally too small, you can neglect difference in elevation (if any) and also it is a safe assumption to consider constant velocity. The pressure drop across the valve then becomes a function of velocity. Express frictional resistance in terms of velocity and equate it to pressure drop.
 

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