(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Suppose an elastic ball is set into projectile motion on an inclined plane, which makes an angle of 30 degrees to the horizontal. It is projected with an initial velocity of 5 m/s, making an angle of 20 degrees to the slope of the plane. Suppose the plane is very long, and no energy loss throughout.

a. Find the time just after the 10th bounce, assume time = 0 when the ball is projected. (g = 10 m/s^2).

b. Hence find the distance travelled by the ball.

2. Relevant equations

x = uxt

y = uyt - .5gt^2

and other equations about projectile motion

3. The attempt at a solution

t' = 2(5 cos 20) / (10 sin 30) = 1.8794 s

So T = 10(1.8794) = 18.8 s.

However the answer is 3.95 s, far smaller than mine.

My instructor gives the answer as follows:

t' = 2(5sin20) / (10cos30) = 0 = 0.395 s

So T = t' * 10 = 3.95 s

I don't really understand what he is doing, and can anyone explain the approach of my instructor?

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# Homework Help: (Mechanics)An interesting question about projectile

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