MHB Mechanics-Conical pendulum, circular motion

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A particle weighing 100 grams is connected to two strings of lengths 30 cm and 50 cm, with point A positioned 30 cm below point B. The discussion focuses on determining the range of angular velocities that allow the particle to move in horizontal circles while keeping both strings taut, with gravity set at 10 m/s². The calculated range for the angular velocity is between 5 and 9.14 radians per second. Key considerations include the equilibrium of vertical tension forces against gravity and the horizontal tension providing the necessary centripetal force. Understanding these dynamics is crucial for solving the problem effectively.
dragonoid122
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A particle of 100 grams is attached by two strings of lengths 30cm and 50cm respectively to points A and B, where A is 30cm vertically below B. Find the range of angular velocities for which the particle can describe horizontal circles with both strings taut. Take g as 10m/s^2

Answer
Show diagram if possible
5<angular velocity<9.14
 
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dragonoid122 said:
A particle of 100 grams is attached by two strings of lengths 30cm and 50cm respectively to points A and B, where A is 30cm vertically below B. Find the range of angular velocities for which the particle can describe horizontal circles with both strings taut. Take g as 10m/s^2

Answer
Show diagram if possible
5<angular velocity<9.14

Welcome to MHB, dragonoid! :)

What is your question?
Can you show some of your thoughts?

Note that the range is limited by the fact by the boundary condition where either there is just no tension on the upper string, or there is just no tension on the lower string.

We will need:
  1. equilibrium between the vertical component of the tensional force and the force of gravity,
  2. the horizontal component of the tensional force equal to the required centripetal force.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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