Mechanics displacement Question

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SUMMARY

The drag racer’s velocity is defined by the equation v = 5t^2, leading to the displacement equation derived through integration. The correct expression for displacement from time t = 0 to time t is 5t^3/3, as confirmed by the manual. The user initially miscalculated the displacement as 5t^3/2 due to a misunderstanding of the integration process. Proper application of calculus is essential for deriving displacement from velocity.

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Homework Statement


At time t = 0 a drag racer starts from rest at the origin and moves along a straight line with velocity given by v = 5t^2, where v is in m/s and t in s. The expression for the displacement of the car from t = 0 to time t is
(a) 5t^3
(b) 5t^3/3
(c) 10t
(d) 15t^2
(e) 5t/2


Homework Equations


(Vfinal-Vinitial/2)t=X
Vfinal=5t^2

The Attempt at a Solution



The manual says B

But I keep Getting 5t^3/2

Vfinal=5t^2

Vinitial=0
so
(5t^2/2)t=x
5t^3/2
 
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u have to apply integration here
 
Oh... I am not versed in calculus at all :l. could you explain the process?
 
express v as ds/dt. then bring the dt to other side of the equation. then integrate both sides.
 
Alright, thanks for your help!
 

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