Mechanics- general motion in a straight line.

[Shah 72]

S for 0 to 2s = 20m
From 2s to 2.5s, I integrated v with limits 2.5 and 2 and got s=8.875m
So total distance would be 28.9m but the textbook ans is 29.9m. Iam not able to get 29.9 m

 

[skeeter]

well depth = $\displaystyle 20 + \int_0^{0.5} 20-t \, dt$

try again

 

[Shah 72]

well depth = $\displaystyle 20 + \int_0^{0.5} 20-t \, dt$

try again

Thanks so much!

 

[skeeter]

Why did your limits of integration not yield the correct solution?

 

[Shah 72]

You know I did try the limit 0.5 but the upper limit I took it as 2. That's the reason I couldn't get the right ans.

After seeing your limits I realized my mistake.
Thanks so much!