- #1

Shah 72

MHB

- 274

- 0

m= 0.08kg, u= 0m/s, s=0.8m, a>0

F=m×a

a1= 10 (sin 16- mu cos16)

V^2=u^2+2as

V^2=16(sin16-mu cos 16)

Coming up= a<0, s=0.1m

Speed is halved

So u^2=8(sin 16- mu cos 16)

a2=-10(sin 16+ mu cos 16)

V^2= u^2+2as

I got 0= 8( sin 16- mu cos 16)-2(sin16+mu cos 16)

I don't get the right ans given in the textbook which is coefficient of friction =0.0956