# Mechanics, specifically Moment question

1. Sep 26, 2010

### SirMarksAlot

1. The problem statement, all variables and given/known data

Also, im not entirely sure what the question is exactly asking. Also, what does the line of action represent?

2. Relevant equations

M = Fx(Perpendicular distance) + Fy(Perpendicular distance)

For couples:

M=Fd

3. The attempt at a solution

i was thinking that i need to find the moment at D, but wouldn't the resultant force still be the same? except located at D? However, since this is a couple, would the moment be the same everywhere?

Last edited: Sep 26, 2010
2. Sep 26, 2010

### Quinzio

A force located at D doesn't give a moment (in D).
You shoud find a force located somewhere else than D.

A hint: the text speaks about LINE of action. Why ?

3. Sep 26, 2010

### SirMarksAlot

Wouldnt the force anywhere still be 48 N since the couple cancels each other out, and leaves only the moment?

Also, is the line of action just the direction/line that the force follows?