1. The problem statement, all variables and given/known data A 3kg body is at rest on a frictionless horizontal air track when a constant horizontal force F acting in the positive direction of an x axis along the track is applied to the body. The force F is applied to the body at t = 0 when the body is at the origin. A stroboscope records the position of the body at 0.5 s intervals. The readings are as follows. Interval (I) 1: 0.04 m I2: 0.2 m I3: 0.44 m I4: 0.8 m How much work is done on the body by the applied force F between t = 0 and t = 2s? 2. Relevant equations K = 1/2mv^2 W = [tex]\Delta[/tex]K s = ut + 1/2at^2 v^2 = u^2 + 2as 3. The attempt at a solution I really have no idea why I'm not getting the right answer. I can't see an error in what I've done. 1) Find a u = 0 a = 2s/t^2 a = 2 x 0.04 / 0.5^2 = 0.32 ms^-2 2) Find v^2 v^2 = ((0 ms^-1)^2) + 2(0.32 ms^-1 x 0.8m) 3) Find the change in kinetic energy and hence the work done [tex]\Delta[/tex]K = 1/2mv^2 = 1/2(3kg)(0.512m^2 s^-2) = 0.768 J --- The answer is meant to be 0.96J. I think I might have done this question months ago but I cannot see where I have gone wrong in the least. Please point out any glaring mistakes :P.