Melting Lightbulb Filaments: What Voltage is Needed?

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SUMMARY

The voltage required to melt the filament of a typical 120V/60W incandescent bulb is approximately 211V, as calculated using the Stefan-Boltzmann law, which translates to a power requirement of 141W. However, standard bulbs are designed for specific wattages at designated voltages, and exceeding these limits can lead to rapid filament failure. Reports indicate that bulbs on lightly loaded circuits may experience higher voltages, causing them to pop. The melting point of tungsten, the material used in filaments, is around 3683K, necessitating careful consideration of voltage and power supply capabilities for experimental setups.

PREREQUISITES
  • Understanding of the Stefan-Boltzmann law for thermal radiation calculations
  • Knowledge of incandescent bulb specifications, including voltage and wattage ratings
  • Familiarity with electrical circuit concepts, particularly voltage and load balancing
  • Basic principles of material science, specifically regarding tungsten properties
NEXT STEPS
  • Research the thermal properties of tungsten and its sublimation characteristics
  • Learn about the effects of voltage on incandescent bulb performance and lifespan
  • Explore the design and operation of photoflood lamps and their voltage tolerances
  • Investigate safe methods for conducting high-voltage experiments with light bulbs
USEFUL FOR

Electrical engineers, physics students, and hobbyists conducting experiments related to incandescent lighting and thermal properties of materials.

elegysix
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Does anyone know an approximate voltage needed to melt the filament of a typical 120V/60W incandescent bulb?

I'm doing a research project and I've calculated 211V. However, I don't have a power supply capable of delivering it - yet. So for now I can't test my theory.

and I haven't had any luck with google.
Any help is appreciated.
 
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Incandescent light bulb filaments don't fail by simple "melting". From what I can tell, the tungsten sublimates under too much heat creating spots along the filament that are thinner and therefore hotter. In a regular modern light bulb that sublimation process is offset by the gases in the glass envelope - even if the bulb is not a halogen.

I can tell you from many reports that when the neutral in a home circuit is disconnected from ground and the load on each side is unbalanced, light bulbs on the lightly loaded (and therefore higher voltage) side will start to pop. From that, I would guess that a standard 60W bulb will not long survive 211 VAC.
 
Thanks. I've been modeling their spectra, voltage, current, resistance, and temperature characteristics.

I want to cause the filament to fail, and I figured raising the filament temperature to the melting point of tungsten (~3683K) would do it. I calculated that I would need 141W using the stefan-boltzmann law, which translated into 211V after modeling the power as a function of voltage.

As you pointed out, I realize there are many more factors involved which I have not yet taken into account. But it's a starting point.
 
I would guess that a standard 60W bulb will not long survive 211 VAC.

not an accurate comment, considering I have lots of 40 and 60 and 75W globes in my house operating at 240V

what is missing is that globes are designed for a specific wattage at a specific voltage


cheers
Dave
 
I believe that photoflood lamps used to be more or less normal bulbs but operated at about 50% over their normal voltage. They would not last more than a few hours at full volts but produce about twice as much light (nice and blue, too)
I just found this link which may be of interest.
 
Thanks sophie, that plot is interesting.


davenn said:
not an accurate comment, considering I have lots of 40 and 60 and 75W globes in my house operating at 240V

what is missing is that globes are designed for a specific wattage at a specific voltage
I did specify 120V/60W. I think his reply was in context.

Moving on, there was a microwave taken apart in our electronics lab this evening. I suspect that tomorrow I'll have the power supply I need to do this test. I'll update with my results if so.
 
elegysix said:
Thanks sophie, that plot is interesting.

I did specify 120V/60W. I think his reply was in context.

Sorry, Yes I missed that in your post
I'll go stand in the corner :wink:


Dave
 
Amazing that those photoflood lamps have a colour temperature of 3200C (which must be more or less the filament temperature in a frosted envelope) whilst the melting point of Tungsten is 3422C. Not a lot of room for error in the supply volts before the filament just gloops.
 
Since I didn't get my power supply yet, here's some pictures of our work so far to keep you interested...

Here are the data sets and models plotted: (disregard the title, as we took data between 174mA and 550mA... I just haven't gotten around to updating that)
Multi_Bulb_No_Table.jpg



and here is a table with the numbers:
datatable.jpg
 

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