Mercury Displacement in a Sealed Tube: Isothermal vs. Adiabatic Processes

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SUMMARY

The discussion focuses on calculating the displacement of mercury in a sealed tube when positioned vertically, considering both isothermal and adiabatic processes. The participant calculated a displacement of 0.072 meters for the isothermal case using the formula F=p*A, where F is force, p is pressure, and A is area. The participant seeks confirmation of their approach and whether a simpler method exists. The isothermal assumption is deemed more reasonable due to the nature of the process involved.

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Homework Statement



A thin tube, sealed at both ends, is 1 m long. It lies horizontally, the middle 10 cm containing mercury at the two equal ends containing air at standard atmospheric pressure. If the tube is now turned to a vertical position, by what amount will the mercury be displaced? Assume that the process is (a) isothermal and (b) adiabatic. Which assumption is more reasonable?

Homework Equations



F=p*A

The Attempt at a Solution



I figured maybe I could calculate the displacement by finding the difference between the two pressures ( or vector sum ) and by using F=p*A and other intermediate equations like that of volume find the displacement.
I got 0.072m of displacement in isothermal case. I think the answer can actually be near the logical one, but i still want to make sure whether I'm using the correct approach.
and maybe there is simpler way to do this?
 
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zygisyyy said:
It lies horizontally, the middle 10 cm containing mercury at the two equal ends containing air at standard atmospheric pressure.


Can you clarify this please?
 
Tube is thin enough so that mercury closes it, separating air on both sides.
 

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