Mesh analysis and power dissipation

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Discussion Overview

The discussion focuses on a problem related to mesh analysis and power dissipation in an electrical circuit, specifically addressing a homework question from an introductory electrical and computer engineering course. Participants explore the calculation of power dissipation for various components within the circuit.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant expresses uncertainty about their calculations for power dissipation and seeks confirmation on their previous solutions.
  • Another participant critiques the assignment's wording, suggesting that the sum of power dissipated in resistors should equal the sum of power delivered by voltage sources, implying a misunderstanding in the assignment's expectations.
  • A later reply provides a method for calculating power dissipation, indicating that the power dissipated by each resistor can be calculated using the formula PR=IR²R, and emphasizes the importance of considering the orientation of the voltage source when calculating its power contribution.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the interpretation of the assignment's requirements, with differing views on how to approach the calculations and the relationships between power dissipation and power delivery.

Contextual Notes

There are indications of potential confusion regarding the assignment's phrasing and the assumptions underlying the calculations, particularly related to the orientation of voltage sources and the summation of power values.

Andriy B
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Hi I'm taking an intro course to electrical and computer engineering and I'm having trouble figuring out part c of number one. I have attached a copy of my solutions to parts a and b which I believe are right (correct me if I'm wrong please) however when I calculate the power dissipation of each component and add them up I get a large number. Thank you in advance.
 

Attachments

  • Matlab_HW_2.pdf
    Matlab_HW_2.pdf
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  • IMG_0300 (1).JPG
    IMG_0300 (1).JPG
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" Determine the power dissipation of each component and show that the sum of the power dissipated equals zero "

Somebody was drunk while writting that assignement ? Dissipative components in that mesh are resistors. Sum of powers dissipated in them must be equal to sum of powers delivered by voltage sources.
 
So what's the correct way to solve part c?
 
After you find current of each branch, calculate power dissipated by every resistor (PR=IR2R).Sum these powers up to find total power dissipated in network. Power contribution of voltage source calculate as PS=Vs⋅I, where I is current through the source (pay attention to voltage source orientation and current flowing through it, depending on network parameters it may be negative). Then show that ∑PR= ∑PS holds
 

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