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Mesh analysis and power dissipation

  1. Oct 29, 2014 #1
    Hi I'm taking an intro course to electrical and computer engineering and I'm having trouble figuring out part c of number one. I have attached a copy of my solutions to parts a and b which I believe are right (correct me if I'm wrong please) however when I calculate the power dissipation of each component and add them up I get a large number. Thank you in advance.

    Attached Files:

  2. jcsd
  3. Oct 29, 2014 #2
    " Determine the power dissipation of each component and show that the sum of the power dissipated equals zero "

    Somebody was drunk while writting that assignement ? Dissipative components in that mesh are resistors. Sum of powers dissipated in them must be equal to sum of powers delivered by voltage sources.
  4. Oct 30, 2014 #3
    So what's the correct way to solve part c?
  5. Oct 31, 2014 #4
    After you find current of each branch, calculate power dissipated by every resistor (PR=IR2R).Sum these powers up to find total power dissipated in network. Power contribution of voltage source calculate as PS=Vs⋅I, where I is current through the source (pay attention to voltage source orientation and current flowing through it, depending on network parameters it may be negative). Then show that ∑PR= ∑PS holds
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