Hi everyone! I'm trying to figure out how to go about this in calculating resistivity of a titanium grade 1 mesh. From what I know the ρ for titanium is 4.3x10^-8 ohm x m. The mesh will be a 1x12inch sheet wrapped cylindrically end to end. Here are the stock values including a change in area. Les also say the temperature of the material is 20°C and grade 1 is equal to 99.9% pure so lets just round that to 100% and ignore impurities. Area: 12x12inches Wire diameter: 0.0020inches = 0.0508mm Width Opening: 0.0080 inches = 0.2032mm Wire Mesh (wires/in): 100 x 100 % open Area: 64% ρ for titanium is 4.3x10^-8 ohm x m I was thinking of using R=(ρ)(Length)/(cross section area of wire) im not an electrical engineer, so any guidance whats so ever would be a great help. Thank you everyone.