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Meson Decay in Relativistic Mechanics

  1. Sep 22, 2008 #1
    1. The problem statement, all variables and given/known data
    The Ko meson is a subatomic particle of rest mass MK = 498 MeV/c2 that decays into two charged pions, Ko [tex]\rightarrow[/tex] [tex]\pi[/tex]positive+ [tex]\pi[/tex]negative. Both pions have the same mass, m[tex]\pi[/tex] = 140 Mev/c2. A Ko at rest decays into two pions. Use conservation of energy and momentum to find the energies, momenta and speeds of the two pions. (Give algebraic answers, in terms of the symbols MK and m[tex]\pi[/tex]. Then plug in numbers.)

    2. Relevant equations
    Total E = Mc2

    Mc2 = (K1 + K2) + (m1 + m2)*c2

    [tex]\Delta[/tex]M = M - (m1 + m2)

    [tex]\Delta[/tex]Mc2 = K1 + K2

    3. The attempt at a solution
    I don't know how to find the energies of the two pions. The back of the book says 249 MeV. MK/2 = 249 MeV but I don't know why. I'm not sure how they got that answer. Any help would be appreciated. Thanks!
  2. jcsd
  3. Sep 23, 2008 #2


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    Because the sum of the total energy of the two pions is equal to the total energy of the K (total energy includes rest mass). To conserve momentum the sum of the momenta of the two pions must be zero, since the initial momentum of the K was zero. That means the momenta are equal and opposite. So they have equal energy.
  4. Sep 23, 2008 #3
    I got it. Thank you!
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