Metal block sliding horizontally

[majinsock]

Homework Statement

A metal block of mass m slides on a horizontal surface that has been lubricated
with a heavy oil so that the block suffers a viscous resistance that varies as the 3/2
power of the speed: F(v) = -cv^3/2

If the initial speed of the block is v_o at x = 0, show that the block cannot travel farther than 2mv_o^1/2/c

Homework Equations

F = ma = m\frac{dv}{dt}

The Attempt at a Solution

So, I took

m\frac{dv}{dt} = -cv^3/2
I rearranged it and got

dv/v^3/2= \frac{-c}{m}dt

I've tried integrating this and I can't seem to end up with the right answer. I'm totally lost. Anyone have any ideas?

EDIT: No help at all?

 

[UltrafastPED]

You are not integrating wrt the correct variables; you need dx, not dt.

Use the chain rule to write dv/dt = dv/dx dx/dt = dv/dx v.

Then when you rearrange the terms you will be integrating dv/sqrt(v) = -c/m dx
The integrals run (v0, v_final) and (0, d); if we carry the integral to v_final = 0 then the distance covered will be d_final.

When I do this I get 2m/c sqrt(v0) = d_final, which supports the expected conclusion.