Method of finding natural frequency

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MissP.25_5
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This is a closed loop system. My teacher showed me that one of the methods to find the natural frequency of this system is by finding the frequency at phase -90 degrees. Why must it be -90 degrees? Please explain. From the phase graph, the frequency at -90 degrees is 32 [rad/s], so that's the natural frequency.
 

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Simon Bridge said:
What does the bode plot tell you?

The bode plot tells us the difference between the asymptote and the real data. Actually, these graphs are plotted for system identification by finding the transfer function G.
 
The bode plot tells us the difference between the asymptote and the real data.
Yes, but what does that mean?

i.e. in the bottom graph you plot a phase against frequency - which phase is this?
The point of these questions is to focus your mind on the physics of the situation that is relevant to your question.
So far you appear to have been concentrating on the math.
 
Simon Bridge said:
Yes, but what does that mean?

i.e. in the bottom graph you plot a phase against frequency - which phase is this?
The point of these questions is to focus your mind on the physics of the situation that is relevant to your question.
So far you appear to have been concentrating on the math.

That means we can see how sensitive the closed-loop transfer function is to the changes in the parameters of the plant transfer function, and also whether the closed-loop system is stable or not.
I am sorry, I don't understand what you mean by "which phase is this".
 
MissP.25_5 said:
I am sorry, I don't understand what you mean by "which phase is this".
What does "-60 degrees" mean, for example? The phase is a numerical value, but where does it come from?